when parents use the xsort method of gender selection

#WHEN PARENTS USE THE XSORT METHOD OF GENDER SELECTION TRIAL#

the test statistic needed to test this claim= 10.92Ĭritical value ( one-tailed) for 0.01 significance level =ĭecision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis. Express the original claim in symbolic form.

The latest results show that among 945 babies born to couples using the XSORT method of gender selection, 879 were girls. Identify the null and alternative hypotheses.

#WHEN PARENTS USE THE XSORT METHOD OF GENDER SELECTION TRIAL#

dhe latest actual results show that among 945 babies born to couples using the XSORT method of gender selection, 879 were girls. When the clinical trial of the XSORT method of gender selection is completed, a formal hypothesis test will be conducted - Answered by a verified Tutor.

Use the sign test and a 0.05 significance level. Test statistic :, where n is sample size, is sample proportion and p is the population proportion. A claim is made that when parents use the XSORT method of gender selection during in-vitro fertilization, the proportion of baby girls is greater than 0.5. When parents use the XSORT method of gender selection, the proportion of baby girls is greater than 0.5. As of this writing, 668 of 726 babies born to parents using the XSORT method of gender selection were girls. Since is right-tailed, so the hypothesis test is a right-tailed z-test.Īlso, it is given that, the sample size : n= 291 I.e The population proportion of giving birth to a boy = 0.5 We know that the probability of giving birth to a boy : p= 0.5 Assuming a 50 rate of female births, find the probability that in. Answer: The test statistic needed to test this claim= 10.92 In a preliminary test of the XSORT method of gender selection, 14 births included 13 girls.

When parents use the xsort method of gender selection